For an 11,000 sq-ft courthouse, the minimum general lighting load is which value?

Prepare for the Independent Electrical Contractors (IEC) Year 4 Exam. Access flashcards, multiple choice questions, and detailed explanations. Enhance your readiness and achieve your certification!

Multiple Choice

For an 11,000 sq-ft courthouse, the minimum general lighting load is which value?

Explanation:
Understanding how the NEC determines the minimum general lighting load: you multiply the floor area by the unit load (in VA per square foot) specified for that occupancy. For a courthouse, the applicable unit load is 1.4 VA per square foot. So for 11,000 ft², the calculation is 11,000 × 1.4 = 15,400 VA. This is the baseline lighting load used before applying any demand factors. The other numbers correspond to different unit loads (e.g., 1.2 VA/ft² would yield 13,200 VA; 1.7 VA/ft² would yield 18,700 VA; 3 VA/ft² would yield 33,000 VA), which is why 15,400 VA is the correct result for this occupancy and size.

Understanding how the NEC determines the minimum general lighting load: you multiply the floor area by the unit load (in VA per square foot) specified for that occupancy. For a courthouse, the applicable unit load is 1.4 VA per square foot. So for 11,000 ft², the calculation is 11,000 × 1.4 = 15,400 VA. This is the baseline lighting load used before applying any demand factors. The other numbers correspond to different unit loads (e.g., 1.2 VA/ft² would yield 13,200 VA; 1.7 VA/ft² would yield 18,700 VA; 3 VA/ft² would yield 33,000 VA), which is why 15,400 VA is the correct result for this occupancy and size.

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy